WebJun 4, 2014 · CBSE Class 10 Answered A 500W electric iron used in a house for 2 hours per day. Calculate the cost to use it for 60 days at Rs 3.20 per kWh. Asked by Topperlearning … WebEnergy consumption calculator. kWh calculator. Energy consumption calculation The energy E in kilowatt-hours (kWh) per day is equal to the power P in watts (W) times number of usage hours per day t divided by 1000 watts per kilowatt: E(kWh/day) = P(W) × t(h/day) / 1000 (W/kW) See also Energy cost calculator Electricity bill calculator
An electric bulb rated for 500 W at 100 V is used in a circuit
WebFind many great new & used options and get the best deals for FEIT ELECTRIC 300W HALOGEN BULB 120V R7S BPQ300T3 2 BULBS at the best online prices at eBay! ... Feit Electric BPQ300T3/CL/T 300 Watt Halogen T3 Bulbs (2) New In Factory Pkg. $7.50 + $5.85 shipping. 5 Bulbs Halogen J Type 100 150 200 300 500W T3 120V R7S 118MM Double … WebMay 30, 2013 · here, the total energy used by 500W electric bulb. E bulb = 500W x 2hrs x 30days = 30000 Wh = 30kWh. and. the total energy used by 0.5 hp (= 373W) motor. E motor = 373 x 5hrs x 30days = 55950 Wh = 55.95kWh. so, total energy consumed. E = E bulb + E motor = 30kWh + 55.95kWh = 85.95kWh. so, total electricity cost will be byjus nationalism
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WebNov 26, 2024 · In Q2, if we go 1 step ahead and try to find the voltage across bulb 2, we will find the voltage is = V = IR = 4 A x 8 Ohm = 32 V. Now as per bulb rating the maximum … WebAn electric bulb has a rating of 500 W, 100 V. It is used in a circuit having a 200 V supply. What resistance must be connected in series with the bulb so that it delivers 500 W? A … WebNov 6, 2024 · The resistance R that must be put in series with bulb so that it draws 500 w is? 2. Relevent equations P= v^2/r I = v/r 3. My attempt at the solution R= V^2/P r (bulb)= 10000/500 = 20 ohm Now for 200 v supply .. P= 500 W V= 200V Rnet = 20 + R R+20= 80 R= 60 ohm But that's not the answer.. why? Last edited by a moderator: Nov 4, 2024 byjus national mock test